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lorasvet [3.4K]
3 years ago
11

Marcy has 567 earmuffs in stock if she can put 18 earmuffs on each shelf, about how many shelves does she need for all of the ea

rmuffs
Mathematics
2 answers:
Nitella [24]3 years ago
8 0

It would be: 567/18 = 31.5

So, she needs atleast 32 shelves....

katrin [286]3 years ago
6 0
Marcy will need 32 shelves to fit all the earmuffs.

32*18=576.

This means that one of the shelves will not be full, but Marcy will still have to use 32 shelves.
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Just plug in an easy number for "x" and solve. Then see if the second problem is really greater that the first
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Given that −4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f
GalinKa [24]

Answer:

\large \boxed{\sf \bf \ \ f(x)=(x-4i)(x+4i)(x+3)(x-5) \ \ }

Step-by-step explanation:

Hello, the Conjugate Roots Theorem states that if a complex number is a zero of real polynomial its conjugate is a zero too. It means that (x-4i)(x+4i) are factors of f(x).

\text{Meaning that } (x-4i)(x+4i) =x^2-(4i)^2=x^2+16 \text{ is a factor of f(x).}

The coefficient of the leading term is 1 and the constant term is -240 = 16 * (-15), so we a re looking for a real number such that.

f(x)=x^4-2x^3+x^2-32x-240\\\\ =(x^2+16)(x^2+ax-15)\\\\ =x^4+ax^3-15x^2+16x^2+16ax-240

We identify the coefficients for the like terms, it comes

a = -2 and 16a = -32 (which is equivalent). So, we can write in \mathbb{R}.

\\f(x)=(x^2+16)(x^2-2x-15)

The sum of the zeroes is 2=5-3 and their product is -15=-3*5, so we can factorise by (x-5)(x+3), which gives.

f(x)=(x^2+16)(x^2-2x-15)\\\\=(x^2+16)(x^2+3x-5x-15)\\\\=(x^2+16)(x(x+3)-5(x+3))\\\\=\boxed{(x^2+16)(x+3)(x-5)}

And we can write in \mathbb{C}

f(x)=\boxed{(x-4i)(x+4i)(x+3)(x-5)}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Answer:

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Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6(x−1)=−2x+50

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6x+−6=−2x+50

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What is the volume of the cone below? ):
svetoff [14.1K]

Answer:

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General Formulas and Concepts:

<u>Symbols</u>

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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Volume of a Cone Formula: \displaystyle V = \frac{1}{3} \pi r^2h

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<u>Step 1: Define</u>

Radius <em>r</em> = 4

Height <em>h</em> = 21

<u>Step 2: Find Volume</u>

  1. Substitute in variables [Volume of a Cone Formula]:                                      \displaystyle V = \frac{1}{3} \pi (4)^2(21)
  2. Evaluate exponents:                                                                                         \displaystyle V = \frac{1}{3} \pi (16)(21)
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3 years ago
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