Suppose you are flying a kite that is 50 feet long. While flying, there is a constant gust of wind that blows the kite to an ang
le of 60° with the ground. How high, in feet, is the kite above the ground
2 answers:
Answer:
Height of the kite above the ground = 43.301270189 feet
Step-by-step explanation:
The illustration above forms a right angled triangle. The right angle triangle have an hypotenuse, adjacent side and opposite sides.
The hypotenuse is given as 50 feet , the angle with the ground is 60°. Using the SOHCAHTOA principle we can find the height of the kite above the ground which is the opposite side .
sine 60° = opposite/hypotenuse
sine 60° = opposite/50
0.8660254038 = opposite/50
cross multiply
opposite = 0.8660254038 × 50
opposite = 43.301270189 feet
Height of the kite above the ground = 43.301270189 feet
The image below is what the illustration forms(right angled triangle)
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