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WITCHER [35]
4 years ago
10

The triangles are similar.

Mathematics
2 answers:
dybincka [34]4 years ago
5 0
36/12=3 Which give you the enlargement of the smaller triangle to the bigger one.

You work out the missing side by putting it into an equation:

3(x-10)=39

Then solve it.

First expand the brackets:

3x-30=39

The rearrange to get x on its own and that will be your answer:

3x=39+30
3x=69
x=69/3
x=23
Sliva [168]4 years ago
3 0

Answer:

x=23

Step-by-step explanation:

The triangles have to be in the same ratio.  Put big triangle side  over little triangle side.

15                  39

----------- = ----------------

5                    x-10

Using cross products

15 * (x-10) = 5 * 39

Divide by 15 on each side

15/15 (x-10) = 5*39/15

x-10 = 13

Add 10 to each side

x-10+10 = 13+10

x=23

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Given a mean score of 1150, standard deviation of 90, and 500 participants, solve the following problem. Using this data and the
expeople1 [14]

Answer:

1. 1056.67

2. 29th percentile.

3. 79

4. 77

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean score of 1150, standard deviation of 90

This means that \mu = 1150, \sigma = 90

1. What is the score for someone in the 15th percentile?

This is X when Z has a p-value of 0.15, so X when Z = -1.037.

Z = \frac{X - \mu}{\sigma}

-1.037 = \frac{X - 1150}{90}

X - 1150 = -1.037*90

X = 1056.67

2. What is the percentile rank of someone with a score of 1100?

This is the p-value of Z when X = 1100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1150}{90}

Z = -0.555

Z = -0.555 has a p-value of 0.29, so 29th percentile.

3. How many students have scores of 1060 or greater?

The proportion is 1 subtracted by the p-value of Z when X = 1060. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1060 - 1150}{90}

Z = -1

Z = -1 has a p-value of 0.1587.

Out of 500:

0.1587*500 = 79

79 is the answer.

4. How many students scored between 1200 and 1250?

The proportion is the p-value of Z when X = 1250 subtracted by the p-value of Z when X = 1200. So

X = 1250

Z = \frac{X - \mu}{\sigma}

Z = \frac{1250 - 1150}{90}

Z = 1.1

Z = 1.1 has a p-value of 0.8643.

X = 1200

Z = \frac{X - \mu}{\sigma}

Z = \frac{1200 - 1150}{90}

Z = 0.555

Z = 0.555 has a p-value of 0.7106

0.8643 - 0.7106 = 0.1537

Out of 500:

0.1537*500 = 77

77 is the answer.

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