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horrorfan [7]
4 years ago
14

Find f. (antiderivative) . f '(t) = 4 cos (t) + sec^2(t), −π/2 < t < π/2, f(π/3) = 3

Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
6 0
The antiderivative of the function f '(t) = 4 cos (t) + sec^2(t) is determined by applying integral calculus. The antiderivative of 4 cos (t) is -4 sin(t) while the antiderivative of <span>sec^2(t) is tan (t). The total term is -4 sin(t) + tan (t). We try to replace pi/3 and the answer is 3.</span>
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A student club holds a meeting. The predicate M(x) denotes whether person x came to the meeting on time. The predicate O(x) refe
Novay_Z [31]

Answer:

a) \exists \, x \in C : O(x) = 0

b) \{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) \{ x \in C: M(x) = 1 \} = C

d) \{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) \exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) \exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

Step-by-step explanation:

  • M(x) = 1 if the person x came to the meeting, and 0 otherwise.
  • O(x) = 1 if the person is an officer of the club and 0 otherwise.
  • D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.

Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.

a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way

\exists \, x \in C : O(x) = 0

b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:

\{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:

\{ x \in C: M(x) = 1 \} = C

d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:

\{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore

\exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have

\exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

I hope that works for you!

7 0
4 years ago
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Murrr4er [49]

Answer:

5(4w-3)

Step-by-step explanation:

4 0
3 years ago
Simplify the expression 5(3x - 7 + 4y)
kolbaska11 [484]

Answer:

15x - 35 + 20y

Step-by-step explanation:

Simplify. Distribute 5 to all terms within the parenthesis:

5(3x - 7 + 4y) =

5 * 3x = 15x

5 * -7 = -35

5 * 4y = 20y

15x - 35 + 20y is your answer.

~

8 0
3 years ago
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gina writes 2 pages per hour write an equation that shows the relationship between the hours spent writing x and the total pages
mart [117]

Answer:

y=2x

Step-by-step explanation:

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3 years ago
Someone help me out with this my grade are bad
eduard

Answer:

2 units tall by 1 unit wide

Step-by-step explanation:

On the given rectangle it tell you the conversion to m is 1 unit = 2 m.

The new figure that needs to be drawn has a conversion of 1 unit = 8m.

So, the fist thing we need to do is calculate the m on the width at the height of the original, which is 16 by 8.

looking at this we can now convert this measurement into our new conversion of 1 unit = 8 m. We can do this by dividing the height and width separately.

Ex:

Since 16 is divided by 8 two times so that gives us the answer of 2 units.

8 is divisible by 8 one time so that gives us the width of 1 unit

if this is confusing just think of it like: x=\frac{16}{8} for the height or x = \frac{8}{8} for the width.

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