Answer:
the centrioles are at opposite poles of the cell
the pairs of homologous chromosomes become arranged on a plane equidistant from the poles called the metaphase plate
spindle fibers from one pole of the cell attach to one chromosome of each pair and spindle fibers from the opposite poles attach to the homologous chromosomes
The answer is <span>They both suggest that snakes evolved from an ancestor with legs.
The second choice is not correct since we have no information about pythons and other snakes. We only have the relationship between geckos, snakes and legless eels. So, it is said that </span><span>snakes in general have more DNA sequences in common with four-legged geckos than they do with legless eels. This means that snakes are closer to geckos than the legless eels. We cannot conclude from this information which evolved from which, but we can say that </span><span>snakes evolved from an ancestor with legs.
In different case, if the snakes had more DNA sequence in common with legless eels, we would conclude that the snakes evolved from an ancestor without legs.</span>
The aquatic organism such as fishes will adapt themselves to have strong fins so as to swim upstream against the current. * The aquatic plants will adapt themselves to grow on the rocks present in the stream. * They may adapt themselves to have a streamlined body that resist being washed downstream by the current.Answer:
Explanation:
Answer:
C)Parental: 41% Dr, 41% dR; recombinant: 9% DR, 9% dr.
Explanation:
The notation Dr/dR for genotypes means that one homologous chromosome has the alleles Dr and the other homologous chromosome has the alleles dR.
The heterozygous plant Dr/dR will produce 4 types of gametes: two identical to the chromosmes the individual has in its somatic cells (called parental), and two gametes which will be a mix of the alleles in the homologous chromosomes (called recombinant).
- Dr: parental
- dR: parental
- DR: recombinant
- dr: recombinant
To calculate the frequency of each type of gamete, we must use the formula:
Distance (map units) / 100 = frequency of recombination.
18 mu / 100 = 0.18.
The total frequency of recombination between the genes D and R is 0.18, but every time crossing over happens, two recombinant gametes are generated. Therefore, each recombinant gamete will have a frequency of 0.18/2=0.09 = 9%.
The frequency of parental gametes will be:
1 - frequency of recombinant gametes
1 - 0.18 = 0.82
But there are 2 parental gametes, so each of them will have a frequency of 0.82/2=0.41 = 41%.
Answer:
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Explanation:
give a picture would help you know