All categories

3 years ago

PLEASE HELP ASAP!!!!

Mathematics

1 answer:

Romashka [77]3 years ago

8 0

Answer:

V is approximately 5572 cm^3

Step-by-step explanation:

A soccer ball is a sphere.

The volume of a sphere is

V = 4/3 pi r^3

V = 4/3 (3.14) (11)^3

= 4/3 * (3.14) 1331

5572.45333333

V is approximately 5572 cm^3

You might be interested in

What is the perpendicular line in slope form of the equation (-5,8);y=1/5x-1

denpristay [2]

Answer: Find the negative reciprocal of the slope of the original line and use the slope-intercept form y=mx+b to find the line perpendicular to y=1/5x−1. y=−5x−17

5 0

3 years ago

Read 2 more answers

Find the derivative of f(x) = 4x + 7 at x = 5.(2 points)

Sveta_85 [38]

Answer:

x=4x+7=

x=5=

Step-by-step explanation:

5 0

3 years ago

Solve for all values of x for -2|x+9|-6=-24

DerKrebs [107]

-2(x+9)-6=-24
-2x-18-6=-24
2x=0
x=0

2(x+9)-6=-24
2x+18-6=-24
2x=-36
x=-18

5 0

2 years ago

Mr.Marquez had 123 eggs in his refrigerator in his restaurant.He put 32 more cartoons of eggs in the refrigerator.Each cartoon c

skad [1K]

Answer:

2790

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

If H is in the interior of ∠EFG, m∠EFH = 75°, and m∠HFG = (10x)°, and m∠EFG = (20x − 5)°, then x = ? and m∠HFG = ?

Diano4ka-milaya [45]

Answer:

$x=8$

$\m\angle HFG= 80^\circ$

Step-by-step explanation:

Given that:

Point $H$ is interior of $\angle EFG$ .

$m\angle EFH = 75^\circ\\m\angle HFG = (10x)^\circ\\m\angle EFG = (20x-5)^\circ$

To find:

$x = ?\\m\angle HFG = ?$

Solution:

First of all, let us represent the given values in the form of a diagram.

Kindly refer to the attached image for the given points and values of angles.

We can clearly see that:

$m\angle EFG = m\angle EFH + m\angle HFG$

Putting all the values given in above equation, we get:

$(20x-5)^\circ = 75^\circ + 10x^\circ\\\Rightarrow 20x-10x=75+5\\\Rightarrow 10x =80\\\Rightarrow \bold{x =8}$

$m\angle HFG =10x^\circ\\\Rightarrow m\angle HFG =10\times 8^\circ\\\Rightarrow m\angle HFG = \bold{80^\circ}$

8 0

3 years ago