so the bridge is 2737 meters long.
at a speed of 322 m/min, meaning for for every passing minute, there are 322 meters covered, so we can simply divide 2737/322 to get a "minute" amount, namely 8.5, at 322 m/min, it takes 8.5 minutes to cross it.
now, if we instead are going slower, at 80 m/min, 80 meters to a minute, then it'll be 2737/80 minutes, namely 34.2125.
their time difference is 34.2125 - 8.5 = 25.7125 minutes, so about 25 minutes and 43 seconds.
The trigonometric function is given as

Apply the half angle identity to find the value of tan 75 ,

Here,

![\tan (75^{\circ})=\frac{\frac{1}{2}}{1-\frac{\sqrt[]{3}}{2}}=\frac{\frac{1}{2}}{\frac{2-\sqrt[]{3}}{2}}^{}](https://tex.z-dn.net/?f=%5Ctan%20%2875%5E%7B%5Ccirc%7D%29%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%7D%7B1-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%7D%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%7D%7B%5Cfrac%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%7D%5E%7B%7D)
![\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}](https://tex.z-dn.net/?f=%5Ctan%2075%5E%7B%5Ccirc%7D%3D%5Cfrac%7B1%7D%7B2-%5Csqrt%5B%5D%7B3%7D%7D)
Now rationalize the function.
![\tan 75^{\circ}=\frac{1}{2-\sqrt[]{3}}\times\frac{2+\sqrt[]{3}}{2+\sqrt[]{3}}=\frac{2+\sqrt[]{3}}{4-3}=\frac{2+\sqrt[]{3}}{1}](https://tex.z-dn.net/?f=%5Ctan%2075%5E%7B%5Ccirc%7D%3D%5Cfrac%7B1%7D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%5Ctimes%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%3D%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B4-3%7D%3D%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B1%7D)
Again simplify the trigonometric function,

Hence the answer is 3.732.
The series is an arithmetic series with first term -10 and common difference (-2-(-10))=8. The general term a_n can be written as
a_n = -10 + 8(n-1)
or
a_n = -18+8n
The last term corresponds to
110 = -18+8n
128 = 8n
16 = n
So, the summation can be written as
<span>the medium coffee cup has a capacity 12 fl-oz volume. the large cup contains 16 fluid ounces capacity in volume. and the extra large, or jumbo cup, is 20 fl oz large. the standard mug size holds 12 fluid ounces of a liquid.</span>
12%=(3+10%*x)/(20+x)
x=30
add 30 pounds of the second alloy