Question

Which of the following equations have infinitely many solutions? Choose all answers that apply: Choose all answers that apply: (Choice A) A x-37=x-37x−37=x−37x, minus, 37, equals, x, minus, 37 (Choice B) B 73x-37=73x-3773x−37=73x−3773, x, minus, 37, equals, 73, x, minus, 37 (Choice C) C 37x-37=37x-3737x−37=37x−3737, x, minus, 37, equals, 37, x, minus, 37 (Choice D) D 74x-37=74x-3774x−37=74x−37

Answer 1

Answer:

All options are correct.

Step-by-step explanation:

In option (A), the given equation is

$x-37=x-37$

Add 37 on both sides.

$x-37+37=x-37+37$

$x=x$

Subtract x from both sides.

$x-x=x-x$

$0=0$

LHS=RHS for all values of x. It means equation x-37=x-37 has infinite many solutions.

Similarly.

In option (B), the given equation is

$73x-37=73x-37$

$73x=73x$

$0=0$

LHS=RHS for all values of x. It means equation 73x-37=73x-37 has infinite many solutions.

In option (C), the given equation is

$37x-37=37x-37$

$37x=37x$

$0=0$

LHS=RHS for all values of x. It means equation 37x-37=37x-37 has infinite many solutions.

In option (D), the given equation is

$74x-37=74x-37$

$74x=74x$

$0=0$

LHS=RHS for all values of x. It means equation 74x-37=74x-37 has infinite many solutions.

Therefore, all options are correct.

Answer 2

Answer:−6x+35=−6x+35