Answer:
The side length of the large square is √2 times larger than the side length of the small square.
Step-by-step explanation:
Suppose we have a small square (square 1) and a large square (square 2). The area of the large square is twice that of the small square, that is,
A₂ = 2 A₁
A₂/A₁ = 2 [1]
The area of a square is equal to the length of the side (l) raised to the second power.
A = l²
l = √A
The ratio of l₂ to l₁ is:
l₂/l₁ = √A₂ / √A₁ = √(A₂/A₁)
We can replace [1] in the previous expression.
l₂/l₁ = √2
The side length of the large square is √2 times larger than the side length of the small square.
Yes, if there's nothing separating the two variables (like "+" or "-") then you'd multiply them.
For example, ab means you multiply a times b.
Just add up the vectors and you are left with a net force of 4N to the left.
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Answer:
m= 1.18605
This is correct, just cut it down to either 1.19 or 1.2
Answer:
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Step-by-step explanation:
