<span><span>Algebra: Exponent and logarithm as functions of powerSolversLessonsAnswers archive </span><span> <span>Click here to see ALL problems on Exponential-and-logarithmic-functions<span><span>Question 726619: <span>Skid mark analysis is one way to estimate the speed a car was traveling prior to an accident. The speed, s, that the vehicle was traveling in miles per hour can be approximated by the formula s=square root 30df, where d represents the length of the skid marks in fee and "f" represents the drag factor of the road. A vehicle that was involved in an accident on an asphalt road was traveling at a speed of 45 mph when it started skidding. If the drag factor for asphalt is 0.75 find the length of the skid marks made by the car. The skid marks made by the car were approximately___________ feet long. </span> (Scroll Down for Answer!)</span>Did you know that Algebra.Com has hundreds of free volunteer tutors who help people with math homework? Anyone can ask a math question, and most questions get answers!<span>OR get immediate PAID help on:</span><span> Go!!!</span></span><span>Answer by </span>stanbon(75310) (Show Source):You can put this solution on YOUR website! <span>s=square root 30df, where d represents the length of the skid marks in feet and "f" represents the drag factor of the road. A vehicle that was involved in an accident on an asphalt road was traveling at a speed of 45 mph when it started skidding. If the drag factor for asphalt is 0.75 find the length of the skid marks made by the car. S = sqrt(30df) 45 = sqrt(30*d*0.75) ---- 45 = sqrt[(90/4)d] ----- 45 = (3/2)sqrt(10d) 30 = sqrt(10d) 10d = 900
d = 90 ft. ================ Cheers, Stan H. </span></span></span></span>
