1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlada-n [284]
4 years ago
11

Which value of k will make x^2-1/4x+k a perfect square trinomial

Mathematics
2 answers:
dezoksy [38]4 years ago
8 0
x^2- \dfrac{1}{4} x+k

To make the expression a perfect square, we always add ( \dfrac{b}{2} )^2:

k =  (\dfrac{1}{4} \div 2)^2

k = (\dfrac{1}{4} \times  \dfrac{1}{2} )^2

k = (\dfrac{1}{8} )^2

k = \dfrac{1}{64}
zvonat [6]4 years ago
7 0
1/64

Your square will be (x - 1/8)^2 which evaluates to x^2 - 1/4x + 1/64.
You might be interested in
In the figure angle 2 and angle 3 are
anygoal [31]
I believe it’s c) complementary
6 0
3 years ago
Can anyone help me, i will give brainiest.
laila [671]

Answer: ∠DOB: 48°

Step-by-step explanation:

1. we need an equation first. the sum of all angles (108°, n°, 2n°) is equal to 180°. we can depict this with the equation: 108°+2n°+n°=180°

2. now we can solve for the missing variable, n.

108°+3n°=180° → subtract both sides by → 3n°=72° → divide both sides by 3 → n=24°

3. now that we know that n=24°, we can solve the value of ∠DOB. we can see that ∠DOB is 2n° which we just plug the number we got for n into the equation. 2*24=48° meaning ∠DOB is 48°

hope this heped! ♡

7 0
2 years ago
Read 2 more answers
20 POINTS!!!
notsponge [240]
8 - 4(x - y) = 2x + 6
8 - 4x + 4y = 2x + 6
-4x - 2x + 4y = 6 - 8
-6x + 4y = -2
6x - 4y = 2 <====
7 0
4 years ago
Read 2 more answers
You have 500 to invest at 3% continuously compounded. How much do you have in five years
tekilochka [14]
The final balance is $580.81.

The total compound interest is $80.81.
5 0
3 years ago
State, with an​ explanation, whether the​ mean, median, or mode gives the best description of the following average. The average
erma4kov [3.2K]

Answer:

The mean is the better method.

Step-by-step explanation:

The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.

The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.

As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.

8 0
3 years ago
Other questions:
  • Shilpa bought 30 T-shirts at a clothing store. 20% of the T-shirts were blue and 1/2 of the T-shirts were black. How many of the
    10·1 answer
  • The shortest leg of a 30º-60º-90º triangle has a length of 6. Find the length of the other leg and the hypotenuse. Write your an
    13·1 answer
  • Did I do any of these wrong ? If so can I get the right answers ? &amp; I need #7
    6·1 answer
  • Translate the sentence into an equation.
    12·1 answer
  • Please help, this is absolute value
    7·1 answer
  • The answer of the problem
    10·1 answer
  • Represent each sum as a single rational number.
    7·1 answer
  • Write a function rule for the following data
    14·2 answers
  • What is 3+√-3 in the form a+bi?
    14·2 answers
  • The graph represents the amount of time it takes an object
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!