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leva [86]
3 years ago
12

Divide 40.83 by 7. Round your answer to the nearest tenth. 5.8 5.9 5.7 5.3

Mathematics
2 answers:
baherus [9]3 years ago
5 0

Answer:

5.8

Step-by-step explanation:

jeka57 [31]3 years ago
4 0

Answer:

5.8

Step-by-step explanation:

40.83 ÷ 7

= 5.833

5.833 rounded up to the nearest tenth = 5.8

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Find the potential solution to the equation log4(2 – x) = log4(–5x – 18).
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HELP, WILL MARK BRAINLIEST+100 POINTS. PLEEEEES Square EFGH is drawn on a coordinate plane. Diagonal FH is on the line y − 3 = n
vova2212 [387]

1) Slope of diagonal GE: 3

2) Equation of the line: x-y=P-Q

3) Slope of the line: 1

4) y-intercept: 4

Step-by-step explanation:

1)

Here the diagonal FH is given by the line with equation

y-3=-\frac{1}{3}(x+9)

This line is written in the form

y-y_0 = m(x-x_0)

where m is the slope of the line and (x_0,y_0) are the coordinates of a point on the line.

Therefore, for line FH we have:

m=-\frac{1}{3} (slope)

(x_0,y_0)=(-9,3)

Diagonal GE is perpendicular to diagonal FH (the diagonals in a square are perpendicular): this means that its slope must be equal to the inverse reciprocal of the slope of FH. THerefore, the slope of diagonal GE is

m_{GE}=-\frac{1}{m_{FH}}=-\frac{1}{-1/3}=3

2)

Two lines are said to be parallel when they have same slope.

Here, we see that the line given in the plot passes through the points

(x_1,y_1)=(0,5)\\(x_2,y_2)=(-3,2)

Therefore the slope of the line shown is

m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-2}{0-(-3)}=1

This means that also the line that we want to find must have slope of 1:

m=1

Now we can use the following form to write the equation of this line:

y-y_0 = m(x-x_0)

where:

m=1

(x_0, y_0)=(P,Q) is the point that must be on the line

Therefore,

y-Q=1(x-P)\\y-Q=x-P\\x-y=P-Q

3)

In order to solve this problem, we have to find the slope of the side WV.

The coordinates of the two points are:

V(a+5,b-1)\\W(a+3,b-3)

Therefore, the slope of side WV is given by:

m=\frac{y_W-y_V}{x_W-x_V}=\frac{(b-3)-(b-1)}{(a+3)-(a+5)}=\frac{-2}{-2}=1

And we said that two lines are parallel if they have same slope: therefore, the slope of the line parallel to the line that contains side VW is also 1.

4)

The line given in this problem has equation:

y=\frac{4}{3}x+1

where

m=\frac{4}{3} is the slope of the line

q=+1 is the y-intercept of the line

Here we want to find the line perpendicular to the given line and passing through the point (4,1).

A line perpendicular to the given one must have a slope which is equal to the negative of the reciprocal of the original one, therefore:

m'=-\frac{1}{m}=-\frac{1}{4/3}=-\frac{3}{4}

Now we can use the form

y-y_0 = m'(x-x_0)

and the coordinates of the point are

(x_0,y_0)=(4,1)

Substituting,

y-1=-\frac{3}{4}(x-4)\\y-1=-\frac{3}{4}x+3\\y=-\frac{3}{4}x+4

We have written the line in the form y=mx+q, with q=4: so the y-intercept is 4.

Learn more about parallel and perpendicular lines:

brainly.com/question/3414323

brainly.com/question/3569195

#LearnwithBrainly

5 0
3 years ago
Read 2 more answers
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