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iVinArrow [24]
3 years ago
12

Descriptive statistics are generally used for which of the following? Check all that apply. To make general conclusions about po

pulations using sample data To describe independent variables only To describe dependent variables only To simplify and summarize data
Mathematics
1 answer:
Tom [10]3 years ago
8 0

Answer:

Correct answer is :

To simplify and summarize data

Step-by-step explanation:

Using sample data we can make inferences about a population using statistical methods such as linear regression. But descriptive statistics, as only describe general characteristics of a sample, can be not generalized to a larger population only by descriptive statistics.

Descriptive statistics (DS) can be used to describe dependent or dependent variables alike. If for example you want to predict the income of a person (dependent) in relation to age, education level ( independent) , descriptive statistics may be used to describe both type of variables the age of the sample or the levels of income.

DS are used basically to summarize data or to make it more simple to analyze.

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What is the distance between the points (11 , -17) and (-11 , -17) in the coordinate plane?
liubo4ka [24]

Answer:

22 units

Step-by-step explanation:

11 - (-11) = 22

8 0
3 years ago
Help me plz with my hw
inna [77]
Circumference is found with the formula

c = pi × d

d is diameter and we will use 3.14 for pi.

The diameter is the measure across the center of the circle. In the first problem, you are given the radius, so we have to multiply by 2 to get the diameter. Then we can use the formula.

12.4 in × 2 = 24.8 in (that's the diameter)

c = pi × D
c = 3.14 × 24.8
c = 77.872 inches

circumference is 77.872 inches.

Try the other problems on your own. They are just like this one. Just make sure they are giving you the diameter and not the radius. Post if you have problems.
6 0
2 years ago
Triangle ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC. Then list the s
Allisa [31]

For line B to AC:  y - 6 = (1/3)(x - 4);  y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14

For line A to BC:  y - 6 = (-1)(x - 0);  y - 6 = -x, so y + x = 6

Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:

(3y - x = 14) + (y + x = 6) =>  4y = 20, y = +5;  Substitute this into y + x = 6:  5 + x = 6, x = +1

<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>

5 0
3 years ago
Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ
Deffense [45]

Answer:

\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}

Step-by-step explanation:

Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}

\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16

\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i

6 0
2 years ago
Read 2 more answers
I need help with this
Softa [21]
Nothing can be done with this question!
8 0
3 years ago
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