Answer:
a type of machine learning based on artificial neural networks in which multiple layers of processing are used to extract progressively higher level features from data.
 
        
             
        
        
        
Answer:
1. row a horizontal set of data in a spreadsheet  
2. spreadsheet software used by many business professionals to work with numbers  
3. data information that is stored  
4. template a file that serves as a starting point for a new document
5. function a built-in formula in a spreadsheet
6. invoice a statement you submit to get paid for a product or service 
Explanation:
The correct matches have been mentioned in the answer section. Certainly, a row is the horizontal set of data is a spreadsheet. And other options are self-understood. And hence, it is self-explanatory. 
 
        
             
        
        
        
#include<stdio.h>
#include<stdlib.h>
int comment1(FILE *fp)
{
    char ch;
    int count=0;
    while(fscanf(fp,"%c",&ch)!=EOF)
    {
        if(ch=='\n')
        {
            return count;
        }
        count++;
    }
    return count;
}
int comment2(FILE *fp)
{
    char ch;
    int count=0;
    while(fscanf(fp,"%c",&ch)!=EOF)
    {
        if(ch=='*')
        {
            fscanf(fp,"%c",&ch);
            if(ch=='/')
            {
                return count;
            }
            count++;
        }
        count++;
    }
    return 0;
}
int main()
{
    printf("Enter the file name:");
    char s[1000],ch,ch1;
    scanf("%s",s);
    FILE*fp;
    fp = fopen(s,"r");
    int count=0;
    while(fscanf(fp,"%c",&ch)!=EOF)
    {
        if(ch=='\"')
        {
            while(fscanf(fp,"%c",&ch)!=EOF)
            {
                if(ch=='\"')
                {
                    break;
                }
                if(ch=='\\')
                {
                    fscanf(fp,"%c",&ch);
                }
            }
        }
        else if(ch=='/')
        {
            fscanf(fp,"%c",&ch);
            if(ch=='/')
            {
                count += comment1(fp);
            }
            else if(ch=='*')
            {
                count += comment2(fp);
            }
        }
    }
    printf("%d\n",count);
    return 0;    
}
 
        
                    
             
        
        
        
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