OMGG SIS I HAVE I READY TO ILL HELP YOU :DDD
Answer:
66 is 49.2537313% of 134
Step-by-step explanation:
so 49.26
Answer:
Step-by-step explanation:
Given that
Group Group One Group Two
Mean 26.00 23.00
SD 2.00 4.00
SEM 0.40 1.21
N 25 11
where group I represents female servers and group II male servers.
We have to calculate confidence interval for 90% for difference in means
The mean of Group One minus Group Two equals 3.00
df = 34
standard error of difference = 0.993
t critical = 2.034 for 90% df 34
Hence confid. interval at 90%
=Mean diff ±2.034 * std error of diff
= (0.98, 5.02)
You would equal the equations together then solve for a variable.
-4x - 3 = -2x + 1
-4x + 2x = 1 + 3
-2x = 4
—— —-
-2 -2
x = -2
then take that x value and substitute it into any one of the equations.
Equation #1
y = -4(-2) -3
= 8 - 3
= 5
Equation #2
y = -2(-2) + 1
= 4 + 1
= 5
Answer:This problem is about linear equations. We assume Dale drive X miles, and the total cost is $Y, then we can get:
Plan I: Y=38+0.11X
Plan II: Y=49+0.07X
When both plans cost the same, 38+0.11X=49+0.07X. We will get X = 275miles, and Y=$68.25
Step-by-step explanation:
