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klio [65]
3 years ago
12

Is it possible for a 5×5 matrix to be invertible when its columns do not span set of real numbers R^5​? Why or why​ not? Select

the correct choice below.
A. It is not​ possible; according to the Invertible Matrix Theorem an n times nn×n matrix cannot be invertible when its columns do not span set of real numbers R^n.
B. It is​ possible; according to the Invertible Matrix Theorem an n times nn×n matrix can be invertible when its columns do not span set of real numbers R^n.
C. It will depend on the values in the matrix. According to the Invertible Matrix​ Theorem, a square matrix is only invertible if it is row equivalent to the identity.
D. It is​ possible; according to the Invertible Matrix Theorem all square matrices are always invertible.
Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

The correct answer is A..

Step-by-step explanation:

From the Invertible Matrix Theorem (IMT) we have a set of equivalent conditions to determine if a square matrix is invertible or not. In particular, it says that a square matrix of dimension tex]n\times n[/tex] is invertible if and only if, its columns span the vector space tex]R^n[/tex].

In the particular case of this exercise we have a matrix of dimension tex]5\times 5[/tex]. So, by the Invertible Matrix Theorem its columns must span the vector space tex]R^5[/tex]. Now, according to the statement of the exercise this condition does not hold. Hence, the given matrix cannot be invertible.

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Which one are these paired to the solution
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Answer:

Option b and d.

Step-by-step explanation:

Given equation : -5x + 4y > -7

Putting the values of x and y one by one in the options,

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Similarly,

b) Putting x as 5 and y as 5.

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c) Putting x as 3 and y as 2.

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This doesn't satisfy the inequality, hence this couldn't be the ordered pair.

d) Putting x as -2 and y as -4.

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This satisfies the inequality, hence this is the ordered pair.

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