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Firlakuza [10]
3 years ago
13

for every 300 kids in high school 2/3 of them take a language. What is the value of a number of students who dont take a languag

e to the number that do?
Mathematics
1 answer:
Anna [14]3 years ago
3 0
All you have to do is divide 300 hundred by 3 and you get 100 students that don’t take a language So 200 students take language and 100 students don’t take language
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What is the value of 2 over 3 to the power of 0 to the power of -3
Schach [20]

Answer:

((\frac{2}{3})^0)^{-3}=1

Step-by-step explanation:

We need to find the value of ((\frac{2}{3})^0)^{-3}

Solving:

We know, (a^b)^n = a^{b*n}

((\frac{2}{3})^{0*-3})

(\frac{2}{3})^0

a^0 = 1

so,

(\frac{2}{3})^0=1

So, the value of ((\frac{2}{3})^0)^{-3}=1

5 0
3 years ago
You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
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ankoles [38]
<h3>Answer:  41 cm^2</h3>

Explanation:

Form a horizontal line as shown below (see attached image). This forms 2 separate smaller rectangles

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The total area is therefore 32+9 = 41 cm^2

You can say "square cm" or "sq cm" in place of the "cm^2".

5 0
2 years ago
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lord [1]
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3 years ago
Need help asap.. thanks​
jonny [76]

Answer: search it up

Step-by-step explanation:

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3 years ago
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