A = -0.7
B = -9/16 (0.5623)
C = -0.4
D = -5/16 (0.3125)
The last option is correct
The domain of the function is [-4, 4) and the range of the function is [-5, 2)
<h3>How to determine the domain and the range of the function?</h3>
<u>The domain</u>
As a general rule, it should be noted that the domain of a function is the set of input values or independent values the function can take.
This means that the domain is the set of x values
From the graph, we have the following intervals on the x-axis
x = -4 (closed circle)
x =4 (open circle)
This means that the domain of the function is [-4, 4)
<u>The range</u>
As a general rule, it should be noted that the range of a function is the set of output values or dependent values the function can produce.
This means that the range is the set of y values
From the graph, we have the following intervals on the y-axis
y = -5 (closed circle)
y = 2 (open circle)
This means that the range of the function is [-5, 2)
Read more about domain and range at:
brainly.com/question/10197594
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Answer:
Blue balloons = 12
Step-by-step explanation:
Total no of balloons = 21
Let us assume that the ratio of blue balloons to green balloons is 4:3.
Let there are 4x blue balloons and 3x green balloons.
ATQ,
4x+3x = 21
7x = 21
x = 3
Blue balloons = 4x
= 4(3)
= 12
Hence, she will have 12 blue balloons at her party.
Answer:
the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444
Step-by-step explanation:
Given the data in the question;
x f(x) xp(x) x²p(x)
1 1/3 0.33333 0.33333
2 1/3 0.66667 1.33333
3 1/3 1.00000 3.0000
∑ 2.0000 4.6667
∑(xp(x)) = 2
∑(x²p(x)) = 4.6667
Variance σ² = ∑(x²) - ∑(x)² = 4.6667 - (2)² = 4.6667 - 4 = 0.6667
standard deviation σ = √variance = √0.6667 = 0.8165
Now since, n = 33 which is greater than 30, we can use normal approximation
for normal distribution z score ( x-μ)/σ
mean μ = 2
standard deviation = 0.817
sample size n = 33
standard of error σₓ = σ/√n = 0.817/√33 = 0.1422
so probability will be;
p( 2.1 < X < 2.4 ) = p(( 2.1-2)/0.1422) < x"-μ/σₓ < p(( 2.4-2)/0.1422)
= 0.70 < Z < 2.81
= 1 - ( 0.703 < Z < 2.812 )
FROM Z-SC0RE TABLE
= 1 - ( 0.25804 + 0.49752 )
= 1 - 0.75556
p( 2.1 < X < 2.4 ) = 0.2444
Therefore, the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444
The formula to find the area of a triangle is
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