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3 years ago

Two angles are supplementary. One angle is 5degrees° more than six times the other. Find the measure of each angle.

Mathematics

1 answer:

kolbaska11 [484]3 years ago

6 0

Well do you know what a supplementary angles is ?
it is two angles that add up to 180 degrees

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nirvana33 [79]

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3 years ago

Read 2 more answers

In plane ABC the measure of angle A equals 42° the measure of angle B is five times the measure of angle C find the measure of a

krok68 [10]

Step-by-step explanation:

I think what is meant in the triangle ABC we have the three angles.

the sum of all angles in a triangle is airways 180 degrees.

so,

180 = A + B + C

180 = 42 + B + C

now, we know also that

B = 5×C

so, we can use that above

180 = 42 + 5×C + C

138 = 6×C

C = 138/6 = 23 degrees

B = 5×C = 5×23 = 115 degrees

7 0

2 years ago

How much chromium-51 will be left after 7 months?

Makovka662 [10]

Answer:

It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

The half-life of chromium 51 is 27.7 days.

After 7 months, chromium 51 will have undergone 7.69 half-lives.

To solve for the ending amount we'll use the formula:

Ending Amount = Beginning Amount / 2^n where 'n' = # of half-lives

We'll say the beginning amount =1

Ending Amount = 1 / 2^7.69

Ending Amount = 0.0048426082

Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

Source: https://www.1728.org/halflife.htm

Step-by-step explanation:

6 0

2 years ago

In triangle ABC, cos A =

nikitadnepr [17]

The other expression that has a value of $\frac{7}{25}$ is A) sin B.

Step-by-step explanation:

Step 1:

$sin\theta = \frac{oppositeside}{hypotenuse} ,$ $cos\theta = \frac{adjacentside}{hypotenuse} ,$ $tan \theta = \frac{opposite side}{adjacent side} .$

For angle B, the opposite side measures 7 units, the adjacent side measures 24 units and the hypotenuse measures 25 units.

$sinB= \frac{oppositeside}{hypotenuse} = \frac{7}{25} ,$ $tan B = \frac{opposite side}{adjacent side} = \frac{7}{24} ,$ $cosB = \frac{adjacentside}{hypotenuse} = \frac{24}{25}.$

Step 2:

For angle A, the opposite side measures 24 units, the adjacent side measures 7 units and the hypotenuse measures 25 units.

$tan A = \frac{opposite side}{adjacent side} = \frac{24}{25} .$

Step 3:

tan C cannot be determined as C is the right angle. The opposite side and hypotenuse of the triangle would be the same.

So sin B also has a value of $\frac{7}{25}.$ This is option A.

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Answer:

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3 years ago