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3 years ago

Two angles are supplementary. One angle is 5degrees° more than six times the other. Find the measure of each angle.

Mathematics

1 answer:

kolbaska11 [484]3 years ago

6 0

Well do you know what a supplementary angles is ?
it is two angles that add up to 180 degrees

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What is the standard form of this equation of a circle?

Olenka [21]

x² + y² + 14x − 4y − 28 = 0

x² +14x +y² - 4y =28
x²+2*7x +7² -7² + y² - 2*2y +2² - 2² = 28
(x+7)² + (y-2)² -7²-2² =28
(x+7)² + (y-2)²=28+49+4

(x+7)² + (y-2)² =81 is the answer.

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3 years ago

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Find the area. 2 ft. 19 ft 4f 5 ft. 7

ch4aika [34]

Answer: 20 ft squared

Step-by-step explanation:

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3 years ago

List all of the factors of 72

True [87]

Well the factors of "72" is→ 1,2,3,4,6,8,9,12,18,24,36,72

To find the factor(s) "72" just write out the muliples that equals 72

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3 years ago

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Which numbers have a digit in the ones place that is 1/10 the value of the digit in the tens place

liq [111]

Answer:

4,099 and 5,011

Step-by-step explanation:

This problem can be solved by taking options one by one.

Option (1) : 4,099

Digit in ones place = 9

The value of the digit in tens place = 90

$\dfrac{9}{90}=\dfrac{1}{10}$ . It is correct.

Option (2) : 4,110

Digit in one places = 0

The value of the digit in tens place = 10

It is incorrect.

Option (3) : 5,909

Digit in one places = 9

The value of the digit in tens place = 0

It is again incorrect.

Option (4) : 5,011

Digit in one places = 1

The value of the digit in tens place = 10

$\dfrac{1}{10}$ . It is correct.

Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.

7 0

3 years ago

Y=4x-6 and passes through point 8,12

umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

$y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20$

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

$y=mx+b\\y=4x-20$

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

$y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14$

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

$y=mx+b\\y=-\frac{1}{4} x+14$

8 0

3 years ago