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Salsk061 [2.6K]
3 years ago
12

Which function has a range of y<3? y=3(2) y=2(3)* y=-(2)* + 3 y= (2)X-3

Mathematics
1 answer:
Bingel [31]3 years ago
3 0

The function that has a range of y<3 is y=-(2)* + 3

Answer: Option(c)

<u>Step-by-step explanation:</u>

Solution:

Lets shall evaluate the options given in the question

In Option 1; y=3(2) that is

y=3 \times 2=6

So the value of y>3 and thus option 1 fails

In option 2; y=2(3)*

This expression indicates that the power of 3 all result in positive values and sometimes zero such that for 2 \times 3^{0}=0 and for values other than one y will be greater than 3. so option 2 fails.

In option 4; y=2x(-3)

On solving we get y=2 \times(-3)=-6

Though it is less than 3 but it has an negative value. So option 4 fails.

In option 3; y=-(2)* + 3

This option indicates for all power values of -2 the y value will be less than 3 such that

For power value 0 we get

y=-2^{0}+3

y=0+3=3

And for the power value 1 we get

y=-2^{1}+3

y=-2+3=1

So in the both the occasion the value of y<3 than and it is not an negative value and thus option 3 satisfy the functional range y<3.

Result:

Thus the function that has a range of y<3 is y=-(2)* + 3

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