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Natasha_Volkova [10]
3 years ago
15

tabia stores her hair bands in a cube shaped container. the cube has a volume of 64 cubic inches. What is the lenght of the edge

s of the cube? ​
Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

The length of the edge of the cube = 4 inches

Step-by-step explanation:

* Lets describe the cube

- It has 6 faces all of them are squares

- It has 8 vertices

- It has 12 equal edges

∵ The volume of any formal solid = area of the base × height

∵ The base of the cube is a square

∴ Area base = L × L = L² ⇒ L is the length of the edge of it

∵ All edges are equal in length

∴ Its height = L

∴ The volume of the cube = L² × L = L³

* Now we have the volume and we want to find the

 length of the edges

∵ Its volume = 64 inches³

∴ 64 = L³

* Take cube root to the both sides

∴ ∛64 = ∛(L³)

∴ L = 4 inches

* The length of the edge of the cube = 4 inches

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\huge \boxed{\mathbb{QUESTION} \downarrow}

  • How do you simplify this?
  • x²y+xy² / y²+2/5 × xy

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\sf\frac{  { x  }^{ 2  }  y+x { y  }^{ 2  }    }{  { y  }^{ 2  }  + \frac{ 2  }{ 5  }   \times  xy  } \\

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_____

<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>

<u>NUMERATOR</u> \downarrow

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<u>DENOMINATOR</u> \downarrow

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\sf \: {\frac{1}{5}y\left(2x+5y\right)}  \\

_____

Continuing...

\sf\frac{xy\left(x+y\right)}{\frac{1}{5}y\left(2x+5y\right)}  \\

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\sf\frac{x\left(x+y\right)}{\frac{1}{5}\left(2x+5y\right)}  \\

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This can further simplified to as \downarrow

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