Given:
The ratio of the cost of a shirt to the cost of a jacket is 2:5.
The jacket cost $240 more than the shirt.
To find:
The cost of the shirt and the cost of the jacket.
Solution:
Let x be the cost of the shirt.
The jacket cost $240 more than the shirt. So, the cost of Jacket is (x+240).
The ratio of the cost of a shirt to the cost of a jacket is 2:5. So,



Subtract 2x from both sides.


Divide both sides by 3.


So, the cost of shirt is $160.
Now, the cost of jacket is:

Therefore, the cost of shirt is $160 and the cost of jacket is $400.
KJ^2=6^2+3^2
KJ=the square root of 36+9
KJ=square root of 45
kJ= 3 times the square root of 5
The answer is D