∆ PQR is congruent to ∆ STU
This means --
P = S
Q = T
R = U
R = 80°
S = P = 70°
So in ∆PQR, we know R = 80° , P = 70° and Q = ?
Using angle sum property of triangle,
P+ Q + R = 180°
70° + 80° + Q = 180°
150° + Q = 180°
Q = 30°
Hope This Helps You!
Answer:
a
Step-by-step explanation:
Answer:
C11=-2
C22=8
hope this will help you more
good luck
Answer:
Evaluate the terms inside of the parentheses
Step-by-step explanation:
According to PEMDAS, you always start solving an equation by answering what is inside of the parentheses first. (That's what the 'P' in PEMDAS stands for!)
Therefore, this is the correct answer.
You must travel at 42 mph for 4 hours
<em><u>Solution:</u></em>
Time varies inversely as rate of motion
Let "t" be the time required
Let "r" be the rate of motion
Then, we get

Where, "k" is the constant of proportionality
<em><u>You travel 3 hours at a rate of 56 mph</u></em>
Substitute t = 3 and r = 56 in eqn 1

<em><u>Find the rate you must travel for 4 hours</u></em>
r = ? and t = 4
Substitute t = 4 and k = 168 in eqn 1

Thus you must travel at 42 mph for 4 hours