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VashaNatasha [74]

4 years ago

13

Evan has a shell collection. On Monday he found 6 new shells. On Tuesday , he gave 9 shells to his friends. After giving the she

lls away, Evan had 37 shells left. How many shells did Evan have to begin with?

1 answer:

Inessa05 [86]4 years ago

5 0

Answer:

52

Step-by-step explanation:

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Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

3 years ago

Royal lawncare company produces and sells two packaged products

MrRa [10]

Royal Lawncare Company produces and sells two packaged products. Weedban and Greengrow. Revenue and cost information relating to the products follow: Product Weedban Greengrow Selling price per unit $ 11.00 $ 36.00 Variable expenses per unit $ 3.00 $ 14.00 Traceable fixed expenses per year $ 136.000 $ 31.000 Common fixed expenses in the company total $96.000 annually. Last year the company produced and sold 37.000 units of Weedban and 15.500 units of Greengrow. Required: Prepare a contribution format income statement segmented by product lines. Product Line Total Company Weedban Greengrow Sales Variable expenses Contribution margin Traceable fixed expenses Product line segment margin Common fixed expenses not traceable to products Net operating income

7 0

3 years ago

Common types of data patterns that can be identified when examining a time series plot include all of the following except _____

topjm [15]

Answer:

Vertical is the answer

6 0

2 years ago

Find the area of the figure.

seraphim [82]

$\huge \bf༆ Answer ༄$

At first Divide the figure into two rectangles, I and Il

Area of figure l is ~

$\sf24 \times (40 - 30)$

$\sf24 \times 10$

$\sf240 \: \: ft {}^{2}$

Area of figure ll is ~

$\sf 18 \times 30$

$\sf540 \: ft{}^{2}$

Area of whole figure = Area ( l + ll )

that is equal to ~

$\sf240 + 540$

$\sf780 \: \: ft{}^{2}$

7 0

2 years ago

Use partial quotients to solve 504 divide 14

miv72 [106K]

Answer:

Perform the following division using partial quotients: 504 ÷ 14:

To reduce the numerator, we will be multiplying the denominator by factors of 10, 5, 2, and 1

Step-by-step explanation:

1 4| 5 0 4

2 8 0 20 <---- 20 x 14 = 280

2 2 4 <---- 504 - 280 = 224

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10 <---- 10 x 14 = 140

8 4 <---- 224 - 140 = 84

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5 <---- 5 x 14 = 70

1 4 <---- 84 - 70 = 14

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5

1 4

1 4 1 <---- 1 x 14 = 14

0 <---- 14 - 14 = 0

Our partial quotients add up as follows:

20 + 10 + 5 + 1 = 36

I hope it helps plz Mark me brainliest:)

5 0

3 years ago