X^2+3x=24, halve the linear coefficient, square it, and add it to both sides
In this case (3/2)^2=2.25
x^2+3x+2.25=26.25 now the left side is a perfect square...
(x+1.5)^2=26.25 take the square root of both sides
x+1.5=±√26.25 subtract 1.5 from both sides
x=-1.5±√26.25
x=-1.5-√26.25 and -1.5+√26.25
x≈ -6.62 and 3.62
Answer:
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Yes the diagonals of a parallelogram have the same midpoint since they ... of the intersection of the diagonals of parallelogram AB CD given the vertex points ... If a parallelogram is a rhombus then its diagonals are? , statement 2 is the answer
