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alekssr [168]
3 years ago
9

The missing number in the arithmetic sequence 60, 51,

Mathematics
1 answer:
Harman [31]3 years ago
8 0

Step-by-step explanation:

missing where ?

I guess you mean that there is one element missing between 51 and 33 (based on the readable answer options).

if that is true, then the missing element is 42.

the difference between 60 and 51 is 9.

the difference between 51 and 33 is 18.

if there is an engender missing in between 51 and 33, then it is logical to put it in the middle cutting the interval of 18 in half to 2 times 9. which is also supported by the first interval between 60 and 51 (9).

so, it would be 51 -9 = 42

You might be interested in
The radius of circle O is 28, and OC =9. What is the length of AB?
aksik [14]
The answer:
the complement of the question proposed one of the choices given beneath:
a) 58.8
b) 53.0
c) 29.4
d) 26.5

as we observe at the figure, AOB an isosceles triangle, and OCB is a right triangle

consider OCB
OC =9, OB= radius = 28
the problem is how to find the length of CA, for that C is a midpoint of segment AB, so AC=BC

BC can be found by using pythagorean theorem
OB²= OC² + CB²,  this implies CB² = OB² - OC²

CB² = 28² - 9² = 784 - 81=703, therefore CB= sqrt (703)=26.51

CB=26.51, since CB= AC, so  AC=CB= 26.51

finally the <span>the length of AB is AB = 2 x CB = 2x AC= 2x 26.51= 53.0
</span>
the answer is b) 53.0

7 0
3 years ago
I need help asap someone please help me i dont understand this question so can someone help me
eduard

Answer:

we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

Step-by-step explanation:

Given the expression

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}

=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}

cancel the common factor: 2

=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}

cancel the common factor: p

=\frac{2p+1}{p^2\left(4p^2-1\right)}

=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}

cancel the common factor: 2p+1

=\frac{1}{p^2\left(2p-1\right)}

Expanding

=\frac{1}{2p^3-p^2}

Thus, we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

7 0
3 years ago
HELP PLEASE!!!
fomenos
1 it’s the most educated guess.
6 0
3 years ago
Nate rented a power washer and a generator. On his first job, he used each piece of equipment for 6 hours which cost $90. On his
sp2606 [1]

Answer:

Step-by-step explanation:

p = power washer and g = generator

6p + 6g = 90 .....multiply by 4

4p + 8g = 100 ....multiply by -6

---------------------

24p + 24g = 360 (result of multiplying by 4)

-24p - 48g = -600 (result of multiplying by -6)

---------------------add

-24g = - 240

g = -240 / -24

g = 10 <=== the generator cost $ 10 per hr

6p + 6g = 90

6p + 6(10) = 90

6p + 60 = 90

6p = 90 - 60

6p = 30

p = 30/6

p = 5 <==== the power washer costs $ 5 per hr

check...

4p + 8g = 100

4(5) + 8(10) = 100

20 + 80 = 100

100 = 100 (correct)

3 0
3 years ago
Plz help meeeee plz
Sauron [17]

Answer:

Less than

Step-by-step explanation:

Its less than because the angle of LS is 98 while MS is 95, so LS is longer

3 0
3 years ago
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