hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
Treat it as a fraction where it must stay equal
6/54
with fractions, you can do anything as long as you do it so top and bottom
so 6/54=1/9=2/18=3/27=4/36=5/45 etc
but don't forget to convert back to ratios
so some examples are 1:9
2:18
3:27
4:35
5:45
Please provide more information and the digits of where the points should be coordinated in a graphic
Answer:
a= -2
b= 1
c= 4
d=0
Step-by-step explanation:
-5 times -2 is 10.
-5 times 1 is -5.
-5 times 4 is -20.
-5 times 0 is 0.
