Answer:
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Sample 4</h3>
Step-by-step explanation:
When there is a large number with 0.1 away from Actual, it is closer than to 20, 32, or 36.
This is the best way I can explain it.
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Answer:
m∠KIJ = m∠LIM ⇒ answer B
Step-by-step explanation:
* Lets explain how to solve the problem
∵ I is the mid-point of NH
∴ IN = IH
- MJ is perpendicular to NH and passes through I the mid-point of NH
∴ MJ is perpendicular bisector of NH
- NH ⊥ MJ and intersects it at I
∴ m∠NIM = m∠NIJ = 90°
- ∠ NIM consists of two angles ∠NIL and ∠MIL
∵ m∠NIM = m∠NIL + m∠MIL
- ∠NIJ consists of two angles ∠NIK and ∠JIK
∵ m∠NIJ = m∠NIK + m∠JIK
∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)
∵ NH bisects ∠KIL
∴ m∠NIL = m∠NIK ⇒ (2)
- From (1) and (2)
∴ m∠MIL = m∠JIK
* m∠KIJ = m∠LIM
Answer:
1st- what scenario are talking about?
2nd- false, becuase if you hide under any objects there is the risk of it falling over you and hurting you
The center of the clock is taken as the origin.The clock is a circle with a diameter 10 units.Radius is half the diameter .Radius = 10 ÷2= 5 units.
The clock is divided in four quadrants .On x axis y=0 and on y axis x=0.
When it is 12 o'clock the hour hand is on positive of y axis.Coordinates of the point at 12 o'clock=(0,5)
When it is 3 o 'clock the hour hand is on positive of x axis .Coordinate of the point at 3o'clock is (5,0)
When it is 6 o'clock the hour hand is on negative of y axis .The coordinates of the point at 6o'clock is (0,-5)
At 9o'clock the hour hand is on negative of x axis .The coordinate of the point at 6o'clock is(-5,0)
