Answer:
spider with second option (spiders have an open circulatory system.)
earthworm with first option
starfish with forth option
Explanation:
Answer:
The correct answer is b. C6H12O6 -> 2 C3H4O3+2 H+
Explanation:
Glycolysis occurs in both the condition aerobic and anaerobic so it does not require oxygen. In glycolysis, one glucose molecule is converted into two pyruvate( 2 C3H4O3) and two 2 ATP, 2NADH, and 2 H₂O are produced.
Initially, 2NAD⁺ is produced during glycolysis which is reduced to produce 2NADH and 2 H⁺. Therefore the correct equation is C6H12O6 -> 2 C3H4O3+2 H+.
Then this pyruvate is used in the Kreb cycle which is required for the complete breakdown of glucose into carbon dioxide and water and this process occurs in aerobic conditions. Complete oxidation is important to produce more energy from partially oxidized glucose.
Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625