Answer:
Amount of paper need = 140 cm²
Step-by-step explanation:
Given:
Length of rectangular prism = 5 cm
Width of rectangular prism = 5 cm
Height of rectangular prism = 4 cm
Base of triangular side = 5cm
Height of triangular side = 6 cm
Find:
Amount of paper need
Computation:
Amount of paper need = Curved surface area of rectangular prism + Curved surface area of square pyramid
Amount of paper need = 2h(l + b) + 4[Area of triangle]
Amount of paper need = 2h(l + b) + 4[(1/2)(b)(h)]
Amount of paper need = (2)(4)(5 + 5) + 2[(5)(6)]
Amount of paper need = (8)(10) + 2[30]
Amount of paper need = 80 + 60
Amount of paper need = 140 cm²
Well compared to the parent function x^2, the graph of y=-3x^2+3 is flipped upside down (negative sign), steeper, and is up 3 units from the origin.
Answer:
JK = 6
NL = 4
Step-by-step explanation:
J > K > M > N > L
JN = 14
KM= 4
MN = 4
LN = 4
JN - KM -MN= JK
14-4-4=JK
JK = 6
if 3 measures are 4 then this is showing radius split into two sectors
JK therefore is segment 1 = 6
KM therefore is segment 2 = 4
MN therefore is the sector radius from M = 4
NL therefore is the sector radius from N to L which meets J and = 4 as it is an end line of the segment.