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Ghella [55]
3 years ago
14

Use the values in the table to determine the slope.

Mathematics
2 answers:
vaieri [72.5K]3 years ago
5 0

Answer:

what htt

Step-by-step explanation:

Hitman42 [59]3 years ago
3 0

Answer:

Xzy

Step-by-step explanation:

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T(1) = 9<br> t(n + 1) = 2 • t(n)
timurjin [86]

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t(1)3 = 914

t(s + 1) = 2 • t(s)

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La expresion 18+2^3 / 4x2
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18+8/4x2
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18+1
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What is the area of one trapezoidal face of the figure?
Arturiano [62]
The area of a trapezoid, A, is the average of the lengths of the bases (B and b) multiplied by the height, h.

A = \dfrac{(B + b)h}{2}

A = \dfrac{(3~in. + 1~in.) \times 1~in.}{2}

A = \dfrac{4~in. \times 1~in.}{2}

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4 years ago
Share £747 in the ratio 2:7 between Tom and Ben
beks73 [17]
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6 0
3 years ago
Apel Sinoman has 100 ft of fencing material to enclose a rectangular exercise run for her dog. One side of the run will border h
Olegator [25]

Answer:

For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

Step-by-step explanation:

Let the length of the rectangular exercise run = l ft

and width of the run = w ft

Sinoman has to cover a rectangular exercise run from three sides with the fencing material,

So length of the material = (l + 2w) ft

l + 2w = 100

l = 100 - 2w --------(1)

Area of the rectangular area covered = Length × width

A = lw

A = w(100 - 2w)    [(l = 100 - 2w)from equation (1)

For maximum area we find the derivative of area and equate it to zero.

\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]

A'=\frac{d}{dw}(100w-2w^{2} )

A' = 100 - 4w

For A' = 0

100 - 4w = 0

4w = 100

w = 25 ft

From equation (1)

l = 100 - 2w

l = 100 - 2×(25)

l = 50 ft

Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.

5 0
4 years ago
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