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Julli [10]
3 years ago
11

What is the constant of proportionality in the equation y=2.5xy=2.5xy, equals, 2, point, 5, x?

Mathematics
2 answers:
earnstyle [38]3 years ago
8 0

Answer:

The constant of proportionality in the given equation is, 2.5

Step-by-step explanation:

The direct proportionality states that:

y \propto x then the equation is in the form of:

y=kx .........[1] ; where, k is the constant of proportionality

Given the equation:

y=2.5x

On comparing equation [1] we have;

k = 2.5

Therefore, the constant of proportionality in the given equation is, 2.5

Alekssandra [29.7K]3 years ago
7 0
<span>The equation is a linear equation 


 Start with the given equation 



 Rewrite  as  




Looking at  we can see that the equation is in slope-intercept form where the slope is  and the y-intercept is  note:  really looks like  


Since  this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis 

So we have one point  

 



Now since the slope is comprised of the "rise" over the "run" this means 
 

Also, because the slope is , this means: 

 


which shows us that the rise is 5 and the run is 2. This means that to go from point to point, we can go up 5 and over 2 



So starting at , go up 5 units 
 

and to the right 2 units to get to the next point  
 


Now draw a line through these points to graph  

 So this is the graph of  through the points </span>
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For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

We multiply both sides by: (\frac {1} {36}) ^ {3n}

216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}

We divide both sides by 216:

\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}

To divide powers of the same base, we place the same base and subtract the exponents:

216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}

Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

To multiply powers of the same base, we place the same base and add the exponents:

6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1

We know that any number raised to zero is 1, a ^ 0 = 1.

So, for equality to be true:

9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1

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n = 1

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