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Arturiano [62]
3 years ago
15

PLEASE HELP!! Factor. 4x^2−49y^2

Mathematics
1 answer:
Zanzabum3 years ago
5 0

Answer:

(2x-7y) (2x+7y)

Step-by-step explanation:

4x^2−49y^2

This is the difference of squares

a^2 - b^2 = (a-b) (a+b)

a^2 =4x^2   so a = 2x

b^2 = 49y^2  so b =7y

4x^2−49y^2 = (2x-7y) (2x+7y)

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Answer:

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Step-by-step explanation:

We need to write the expansion of Binomial (2x - 3)⁵

Here general form of binomial expansion is:

(a + b)ⁿ = ⁿC₀aⁿ + ⁿC₁aⁿ⁻¹b + ⁿC₂aⁿ⁻²b² + ⁿC₃aⁿ⁻³b³ + ... + ⁿCₙbⁿ

(2x - 3)⁵= ⁵C₀(2x)⁵ + ⁵C₁(2x)⁵⁻¹(-3) + ⁵C₂(2x)⁵⁻²(-3)² + ⁵C₃(2x)⁵⁻³(-3)³  

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(2x - 3)⁵= (32x⁵) + 5(16x⁴)(-3) + 10(8x³)(-3)² + 10(4x²)(- 3)³ + 5(2x)(-3)⁴+(-3)⁵

(2x - 3)⁵= 32x⁵ - 240x⁴ + 720x³ - 1080x² + 810x - 243                

That's the final answer.

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