Answer:
False
Step-by-step explanation:
Consider the equations with the same number of equations and variables as shown below,
<u>Case 1</u>
![x_{1} + x_{2} = 0\\x_{1} + x_{2} = 1](https://tex.z-dn.net/?f=x_%7B1%7D%20%2B%20x_%7B2%7D%20%3D%200%5C%5Cx_%7B1%7D%20%2B%20x_%7B2%7D%20%3D%201)
This equation has no solution because it is not possible to have two numbers that give a sum of 0 and 1 simultaneously.
<u>Case 2</u>
![x_{1} + x_{2} = 1\\2x_{1} + 2x_{2} = 2](https://tex.z-dn.net/?f=x_%7B1%7D%20%2B%20x_%7B2%7D%20%3D%201%5C%5C2x_%7B1%7D%20%2B%202x_%7B2%7D%20%3D%202)
This equation has infinitely many possible solutions.
Therefore it is FALSE to say a linear system with the same number of equations and variables, must have a unique solution.
To find the mean add up all the numbers and divide. The mean absolute deviation is the difference.
Answer:
A - 23
B - Finn and 16
Step-by-step explanation:
Counting each box until you get to C gives you 23 and 16 from points A and B
1) Given binomials:
First binomial 7r - 5
Second binomial 5r + 8
2) To pass from 7r to 5r you have to subtract 2r, so the first term of the binomial to be subtracted is 2r
3) To pass form - 5 to + 8, you have fo subtract - 13
4) So the answer is 2r - 13, option b.
Answer:
3+2+2-1+2=8
Step-by-step explanation:
Hope this helps!