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3 years ago

Write the expanded form, for 34.75

Mathematics

2 answers:

aalyn [17]3 years ago

7 0

Answer:

30+4+0.7+0.05

Step-by-step explanation:

Because expanded form is add the number.

3=30

4=4.

7=0.7

and 5=0.05 so all together is 30+4+0.7+0.05

ira [324]3 years ago

6 0

Answer:

Step-by-step explanation:

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write an expression for add 2 and 4 and multiply the sum by 3 next add 5 to that product in double the results

Rzqust [24]

So let's start from the beginning.

Add 2 and 4:

(2 + 4)

Multiply the sum by 3:

3(2 + 4)

Then add 5 to that product:

3(2 + 4) + 5

Then double the results:

2[3(2 + 4) + 5]

8 0

3 years ago

Identify the sampling technique used for the following study. A scientist chooses twenty people at random from each class.

Dmitry [639]

The sampling technique used when A scientist chooses twenty people at random from each class is stratified sampling.

<h3>What is stratified sampling?</h3>

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6 0

1 year ago

Given:

V125BC [204]

Answer:

10 since its half of the original

6 0

3 years ago

Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx

Rudiy27

If we use the substitution $u = \tan x$ , then $du = \sec^2 {x}\ dx$ . If you try substituting just $u$ and $du$ into the integrand, though, you'll notice that there's a $\sec^2x$ left over that we have to deal with.

To get rid of this problem, use the identity $\tan^2 x + 1 = \sec^2 x$ and substitute in the left side of the identity for the extra $\sec^2x$ , as shown:

$\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx$
$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$

From there, we can substitute in $u$ and $du$ , and then evaluate:

$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du$
$= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}$
$= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})$
$= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}$

8 0

3 years ago

What would be the first step to solve the equation for r ?<br> 7 = 15 +r

Oxana [17]

Answer:

the first step should be of subtracting 15 from 7

6 0

3 years ago