Help me please thank you

Please help me on this

Nastasia [14]

Answer:

Points H, J, G, and K

Step-by-step explanation:

For quadrats the right top is 1

left top is 2

left bottom is 3

right bottom is 4

and it is asking for the forth one so look at the right bottom "square"

G and K are on the line but that still makes them part of a Quadratic Just they get to be part of 2 of them like...

G is 3 and 4

K is 1 and 4

5 0

2 years ago

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<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5

Morgarella [4.7K]

Answer:

$=5x+1$ or $=5x-1$

Step-by-step explanation:

One is given the following equation:

$5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}$

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation. Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

$(a-b)^2=a^2-2ab+b^2$

$=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}$

$=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}$

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

$=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}$

$=5x-\frac{|3x-1|}{-(3x-1)}$

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

$|a-b|\\=a -b$ or $(-a-b) = b-a$

$=5x-\frac{|3x-1|}{-(3x-1)}$

$=5x-\frac{3x-1}{-(3x-1)}$ or $=5x-\frac{-(3x-1)}{-(3x-1)}$

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

$=5x-\frac{3x-1}{-(3x-1)}$ or $=5x-\frac{-(3x-1)}{-(3x-1)}$

$=5x-(-1)$ or $=5x-(1)$

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

$=5x-(-1)$ or $=5x-(1)$

$=5x+1$ or $=5x-1$

6 0

2 years ago

16) (1 Point) : Solve the equation

Marat540 [252]

Answer:

(B)

4 +/- 3 sqrt(2) or 4+3sqrt(2) and 4-3sqrt(2)

Step-by-step explanation:

4(c-4)^2=72

4(c-4)(c-4)=72

foil the parenthesis (first, outside, inside, last)

4(c^2 -4c -4c +16)=72

4(c^2-8c+16)=72

divide each side by 4

c^2-8c+16=18

subtract 18 from both sides

c^2-8c-2

use quadratic formula

((-b +/- sqrt((-b^2)-4ac)))/2a

((-(-8)+/-sqrt((-8)^2-4(1)(-2)))/2(1))

(8+/-sqrt(64-(-8)))/2

(8+/-sqrt(64+8))/2

(8+/-sqrt(72))/2

(8+/-sqrt(36 * 2))/2

(8+/-6sqrt(2))/2

4+/-3sqrt(2)

or 4+3sqrt(2) and 4-3sqrt(2)

3 0

2 years ago

How can emily use the above to make an estimate for 576 ÷8

Grace [21]

Given the equation :

$576\div8$

We will use estimation to find the value of the given expression

So, the best estimation for the number 576 is = 600

The best estimation for the number 8 is = 10

So, the given expression is approximately = 600 ÷ 10 = 60

===================================================================

We can calculate the error of the approximation as following :

The actual value is : 576 ÷ 8 = 72

So, the difference is = 72 - 60 = 12

so, the percentage of error will be :

$\frac{12}{72}\cdot100=16.7\%$

7 0

7 months ago

Given the following sets.

svet-max [94.6K]

It looks like the ∩ sign may be missing from the question. If you mean to find A∩C, called the intersection, you're looking for elements that are both in A and C.

{0, 2} qualifies.

6 0

3 years ago

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