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3 years ago

Please help!! due by 11:59 pm, will give brainly !!!

Mathematics

2 answers:

Yanka [14]3 years ago

7 0

Answer:

ALRIGHT BOIS WHERE DONG THIS

Difficulty: Effortless

Step-by-step explanation:

=−12

−9

=−9

kinda eazy guys you just have to copy the numbers

Anton [14]3 years ago

4 0

Answer:

sorry bro school's out I only know basic stuff

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uysha [10]

Answer:

The temp at sunset was 16 degrees

Step-by-step explanation:

-2 + 18 = 16

5 0

3 years ago

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When solved for x, what is the sum when the roots of the quadratic equation are added?

Anna35 [415]

Answer:

Step-by-step explanation:

x² + 10x + 24 = 0

Here, a = 1, b = 10, c = 24. Factoring using the AC method:

ac = 1×24 = 24

Factors of 24 that add up to 10 are +4 and +6.

Therefore:

(x + 4) (x + 6) = 0

x + 4 = 0, x + 6 = 0

x = -4, x = -6

The roots are -4 and -6. Added together:

-4 + -6 = -10

Answer A.

6 0

3 years ago

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Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

4 years ago

PLZ PLZ HELP!! BRAINLIEST IF RIGHT!!

Leona [35]

4xy^2 4*squareroot*xy ?

6 0

4 years ago

Kiley gathered the data in the table. She found the approximate line of best fit to be y = 1.6x – 4. A 2-column table with 5 row

Dimas [21]

Answer:

The residual value is -1.8 when x = 3

Step-by-step explanation:

We are given the following table

x | y

0 | -3

2 | -1

3 | -1

5 | 5

6 | 6

Residual value:

A residual value basically shows the position of a data point with respect to the line of best fit.

The residual value is calculated as,

Residual value = Observed value - Predicted value

Where observed values are already given in the question and the predicted values are calculated by using the equation of line of best fit.

$y = 1.6x - 4$

When we substitute x = 3 in the above equation then we would get the predicted value.

$y = 1.6x - 4 \\\\y = 1.6(3) - 4 \\\\y = 4.8 - 4 \\\\y = 0.8$

So the predicted value is 0.8

From the given table, the observed value corresponding to x = 3 is -1

So the residual value is,

Residual value = Observed value - Predicted value

Residual value = -1 - 0.8

Residual value = -1.8

Therefore, the residual value is -1.8 when x = 3

Note: A residual value closer to 0 is desired which means that the regression line best fits the data.

5 0

3 years ago

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