The order of growth execution time of the push operation when using the LinkedStack class, assuming a stack size of N is; O(1)
<h3>Understanding Computer Programming Language</h3>
Let Top be the position of last element inserted in Array.
For Push operation, the process is as follows;
if(Top == last index of Array) {
Printf(“Stack Overflow”)
} else {
Top = Top + 1
a[Top] = element you want to insert
}
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National FFA is the answer to your question my guy.
Answer: The amount of interest to be paid is $972
Explanation: This is gotten by firstly getting the amount of money to return per year without the interest which is $114400/10(years)= 11440
11440 is to be paid per year without interest. To get amount of interest is $11440*8.5/100 = $972 this is the amount of interest to be paid per year including in year 2.
Therefore, total amount of money together with interest to be paid each year and in year 2 = $11440+$972=12412.
Answer:
public class SimpleSquare{
public int num;
private int square;
public SimpleSquare(int number){
num = number;
square = number * number;
}
public int getSquare(){
return square;
}
}
Explanation:
*The code is in Java.
Create a class called SimpleSquare
Declare two fields, num and square
Create a constructor that takes an integer number as a parameter, sets the num and sets the square as number * number.
Since the square is a private field, I also added the getSquare() method which returns the value of the square.