Answer:
The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
![rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)](https://tex.z-dn.net/?f=rank%28A%29%3Drank%5Cleft%20%28%20%5Cleft%20%5B%20A%7CB%20%5Cright%20%5D%20%5Cright%20%29%5C%3Aand%5C%3An%3Drank%28A%29)
Then satisfying this theorem the system is consistent and has one single solution.
Explanation:
1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
Then the system is consistent and has a unique solution.
<em>E.g.</em>
2) Writing it as Linear system
3) The Rank (A) is 3 found through Gauss elimination
4) The rank of (A|B) is also equal to 3, found through Gauss elimination:
So this linear system is consistent and has a unique solution.
~Hello there! ^_^
Your answer: Hordes of surreptitiously infiltrated computers, linked and controlled remotely, also known as zombie networks are known as..?
Your answer: Hordes of surreptitiously infiltrated computers, linked and controlled remotely, also known as zombie networks are known as botnets.
Hope this helps~
Answer:
The answer is "Option A".
Explanation:
The elliptical curve cryptography system needs much shorter keys for cryptography, and it is very powerful because of the RSA cryptography method. It is also known as a key of 1024-bit, which is in comparison is equal to the 160-bit ECC key for cryptographic, that's why other options are not correct, which is defined as follows:
- In option B, It is higher the ECC key system, that's why it's wrong.
- In option C, It is a part of the RSA system but its value doesn't match the ECC system, that's why it is wrong.
- In option D, It's valued is just double to the RSA system, that's why it is wrong.
Answer:
The circular individually linked list is more efficient for time sharing process ,when multiple application are running on pc it is responsibility of an output system to put all process on a list and execute them all by giving them piece of time and make them wait when cpu is selected to other process.
It will be more suitable for output system to use circular list as when it reaches to last of list it will be manually reaches to starting node or process.
Singly circular linked list is used when we are concerned with the memory as only one process will be allocated memory at once and there are no chances of process to go never-ending waiting.
Explanation:
Answer:
This is how a magnetic hard drive works
Explanation:
The hard drive contains a spinning platter with a thin magnetic coating. A "head" moves over the platter, writing 0's and 1's as tiny areas of magnetic North or South on the platter. To read the data back, the head goes to the same spot, notices the North and South spots flying by, and so deduces the stored 0's and 1's.
Hope it helps pls mark as brainliest
