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const2013 [10]
3 years ago
12

I am doing keyboarding keyboarding is very boring and yeah

Computers and Technology
2 answers:
Bingel [31]3 years ago
7 0

Answer:

yes I agree with you

Explanation:

I have been keyboarding for the past 7 hours.

Akimi4 [234]3 years ago
3 0
I remember I did that last year and it was boring-
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Assume that the classes listed in the Java Quick Reference have been imported where appropriate.
Neko [114]

The following java code will be written for the prescribed

<u>Explanation:</u>

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

7 0
4 years ago
Whats 400000 time 93823
Fynjy0 [20]
Its 375,292,000,00





Yay.....
7 0
3 years ago
Read 2 more answers
What are some examples of everyday coding? (ex: phones, computers, etc.)
Maslowich
Im guessing you mean where coding is used?
pretty much anything with lights or a button

but, examples:
(some) watches
(newer) cars
planes
boats
credit cards (using one requires code to be ran)
Cash registers
(some) safes
Alarm Clocks
Routers
ATMs
eBooks
Cellular Sattelites
Weather Sattelites
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Water Plants
Sewage
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3 years ago
Your co-worker who went to UCLA tells you that DHCP is not enabled at your new job, so you should just use the same IP address t
Aleonysh [2.5K]

Answer:

1. internet connection is not enabled on the computer.

2. The DHCP server in the company is not enabled as well.

Explanation:

For a user to access the internet, the computer must have a public IP address that is either assigned to it by a service provider or dynamically from the DHCP server in the computer. In the case of the former, the user just needs to enable the internet connection to obtain the unique IP address.

If the DHCP server or the internet connection is not enabled, the user would not have access to the internet.

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Which of the following is the MOST important consideration when planning your budget?
nata0808 [166]
<span>Budget for fixed expenses before flexible expenses.</span>
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4 years ago
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