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wlad13 [49]
3 years ago
7

What is the product of these binomials? (x – 6)(x + 2)

Mathematics
2 answers:
LenaWriter [7]3 years ago
7 0
(x-6)(x+2) = x(x+2) - 6(x+2) = x^2+2x-6x-12 = x^2 - 4x - 12 Answer
kicyunya [14]3 years ago
4 0
X^2 - 4x - 12

I use the box method for this, so I set up a box and place one equation on the top and the second on the side.

Then I multiply, combine like terms, and get my final answer.

Hope this helps!
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What is the greatest common denominator
Eva8 [605]
3 is the greatest common denominator
5 0
3 years ago
If y=1/2*x+3, which ordered pair is one of the solutions for the equation and the coordinates for one of the points on
AleksAgata [21]

Step-by-step explanation:

D (-2,2)

:) good day

good day

6 0
3 years ago
9, 2.5, –4, –10.5, –17, .
Vedmedyk [2.9K]
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7 0
3 years ago
There are five identical blue books, two identical green books, and three identical black books. How many different patterns can
dsp73

Answer:

2520 patterns

Step-by-step explanation:

In 'n' 10!  ways, books can be arranged. But, there are also 5! permutation of blue books 'n1', 2! permutation of identical green books 'n2', and 3! permutation identical black books 'n3'.

Therefore, for non identical arrangements:

\frac{n!}{n1!n2!n3!}

\frac{10!}{5!2!3!} = 2520

Therefore, the books can be arranged on a shelf in 2520 patterns

8 0
3 years ago
The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

T19 = $45,4120

n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

y = 20500 + 481800

y = $502300

6 0
3 years ago
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