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KengaRu [80]
3 years ago
13

Convert 0.0000001 to a power of 10. 107 10−7 106 10−6

Mathematics
2 answers:
Westkost [7]3 years ago
7 0
I think it's  10^-7 hope that helps
Alex787 [66]3 years ago
5 0

Answer:

10^{-7}

Step-by-step explanation:

Convert 0.0000001 to a power of 10.

When we convert a decimal number to a power of 10, we put negative power over 10 that is equal to the number of places we have shifted to right.

Now, in 0.0000001, we have 6 zeroes after decimal. And if we are writing it as 10, we need to shift 7 places to right.

The answer will be 10^{-7}

We can also simplify like = \frac{1}{10000000} that becomes 10^{-7}

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Read 2 more answers
The total claim amount for a health insurance policy follows a distribution with density function 1 ( /1000) ( ) 1000 x fx e− =
gizmo_the_mogwai [7]

Answer:

the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

Step-by-step explanation:

The probability of the density function of the total claim amount for the health insurance policy  is given as :

f_x(x)  = \dfrac{1}{1000}e^{\frac{-x}{1000}}, \ x> 0

Thus, the expected  total claim amount \mu =  1000

The variance of the total claim amount \sigma ^2  = 1000^2

However; the premium for the policy is set at the expected total claim amount plus 100. i.e (1000+100) = 1100

To determine the approximate probability that the insurance company will have claims exceeding the premiums collected if 100 policies are sold; we have :

P(X > 1100 n )

where n = numbers of premium sold

P (X> 1100n) = P (\dfrac{X - n \mu}{\sqrt{n \sigma ^2 }}> \dfrac{1100n - n \mu }{\sqrt{n \sigma^2}})

P(X>1100n) = P(Z> \dfrac{\sqrt{n}(1100-1000}{1000})

P(X>1100n) = P(Z> \dfrac{10*100}{1000})

P(X>1100n) = P(Z> 1) \\ \\ P(X>1100n) = 1-P ( Z \leq 1) \\ \\ P(X>1100n) =1- 0.841345

\mathbf{P(X>1100n) = 0.158655}

Therefore: the approximate probability that the insurance company will have claims exceeding the premiums collected is \mathbf{P(X>1100n) = 0.158655}

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2 years ago
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