We have to break each degree in terms of 90
A) 
Which is in third quadrant, therefore sine is negative hence

B) 
Which is in third quadrant, therefore cosine is negative hence

C) 
Which is in third quadrant, therefore tangent is positive hence

D) 
Which is in third quadrant, therefore cosec is negative hence
not defined
E)
Which is in third quadrant, therefore secant is negative hence

F) 
Which is in third quadrant, therefore tangent is positive hence
not defined
Hence only
and
have value -1
Hope this will help
Answer:
3rd 1 hope this helps
Step-by-step explanation:
Answer:
4 4 0 1
Step-by-step explanation:
Q1. 4
Q2. 4
Q3. 0
Q4. 1
The vertex is at (0, 3) so y=a(x-0)²+3, which is y=ax²+3
next, use a given point to find a: 10=a(3)²+3, so 9a=7, a=7/9
the equation is then y=

as for the first question, the shape is an ellipse, the domain is -5≤x≤5, the range is -3≤y≤3
the equation can be written as :