Answer: There are 97 nickels and 108 quarters.
Step-by-step explanation:
Let x = Number of nickels, y = Number of quarters.
As per given,
x+y = 205 ...(i)
0.05x+0.25y = 31.85 ... (ii) [1 nickel = $0.05, 1 quarter = $ 0.25]
Multiply (ii) by 20, we get
x+5y=637 ...(iii)
Eliminate (i) from (iii)
4y = 432
⇒ y = 108 [Divide both sides by 4]
Put value of y in (i), we get
Hence, there are 97 nickels and 108 quarters.
Answer:
Part 1) see the procedure
Part 2)
Part 3)
Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
Step-by-step explanation:
Part 1) Define a variable for the situation.
Let
x ------> the number of months
y ----> the total cost monthly for website hosting
Part 2) Write an inequality that represents the situation.
we know that
Site A
Site B
The inequality that represent this situation is
Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B
Subtract 4.95x both sides
Divide by 5 both sides
Rewrite
Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.
The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months