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alekssr [168]
2 years ago
14

For a certain company, the cost for producing x items is 60x+300 and the revenue for selling x items is 100x−0.5x2 .

Mathematics
1 answer:
Katen [24]2 years ago
7 0

The answers are

  • A. The equation for the profit from selling the items is P =  40x-0.5x²-300.
  • b. The values of x are 10 and 70.
  • c. It is not possible to have the profit of 2500

<h3>How to solve for the expression</h3>

We have the cost function in this question to be

C(x) = 60x+300

We have the function of the revenue to be

Revenue = 100x−0.5x²

A. The formula for revenue function is given

revenue - cost

This is expressed as

= (100x−0.5x²)-60x+300

We have to collect like terms and open the equation above.

This given us:

<h3>40x-0.5x²-300</h3>

B. when profit = 50$

We have p = 40x-0.5x²-300

50 = 40x-0.5x²-300

Multiply the two sides by 10

This gives

500 = 400x - 5x² - 3000

This gives a quadratic equation

5x² - 400x - 3500 = 0

To solve the equation you have to make use of a quadratic calculator.

This gives us the values

<h3>x = 10</h3><h3>x = 70</h3>

c. We have  P =  40x-0.5x²-300.

at P = 2500

2500  =  40x-0.5x²-300.

Multiply the equation by 10

25000 = 400x - 5x² - 3000

collect like terms

400x - 5x2 - 3000 +28000

400x -5x2 +28000

We have to take the discriminant

-400² - 4*5*28000

= -400000

The discriminant is negative hence it is not possible.

Read more on quadratic polynomials here:

brainly.com/question/25841119

#SPJ1

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