Please help me out with this question!

Mathematics

1 answer:

kirill [66]3 years ago

4 0

180-132=48
1 is 48
2 is 132
3 is 48

Don't forget to thank me

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Please help me solve this problem

Stells [14]

Answer:

$180

Step-by-step explanation:

To solve, we can set up a proportion and solve.

You earn $45 for 7.5 hours of work, and you earn $ x for 30 hours of work

45/7.5=x/30

Cross multiply

45*30=7.5*x

1350=7.5x

To solve for x, we need to get x by itself. It is being multiplied by 7.5. To undo this, divide both sides by 7.5

1350/7.5=7.5x/7.5

180=x

So, for 30 hours of work, you would earn $180

5 0

3 years ago

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1 gal3 qt+2qt3pt I don’t know how to do this

kaheart [24]

Hello it would be 2.62500 US gallons hope it helped

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2 years ago

A clinical trial was conducted to test the effectiveness of the drug zopiclone for treating insomnia in older subjects. Before t

aleksklad [387]

Answer:

We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.

Step-by-step explanation:

The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:

$IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}$

Knowing that $t_{0.99,15} = 2.602$ :

$IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516$

$IC[\mu ; 98\%] = [71.387 ; 126,416]$

Note that $102.8 \in [71.384 ; 126.416]$ so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.