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RideAnS [48]
3 years ago
14

Please help me figure this out! Thank you so much :( i really need it! ❤️

Mathematics
1 answer:
Hoochie [10]3 years ago
8 0

Answer:

  \textbf{A. }x=2i\text{ or }x=-2i\\\\\textbf{B. }(x+2i)(x-2i)

Step-by-step explanation:

The quadratic can be solved in a straightforward way:

  x^2+4=0\\\\x^2=-4\qquad\text{subtract 4}\\\\x=\pm\sqrt{-4}\qquad\text{take the square root}\\\\x=\pm2i\qquad\text{simplify}

This tells you that the solutions are ...

  2i or -2i

__

For each root of "a", (x -a) is a factor. Thus the factors of the equation are ...

  (x +2i)(x -2i)

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Answer:

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Step-by-step explanation:

this is how i got it:

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5 0
3 years ago
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saul85 [17]

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Solving by elimination <br> 5x+2y= -3<br> 3x+3y=9<br> please help me solve x and y
-Dominant- [34]
1) -3(5x+2y=-3)⇒ -15x-6y=9
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2) -9x/-9=27/-9 ⇒ x=-3 

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Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em> 

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3 years ago
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