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Mrrafil [7]
3 years ago
15

Let f(x)=241+3e−1.3x . What is the point of maximum growth rate for the logistic function f(x) ? Round your answer to the neares

t hundredth.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
5 0

Answer:

The point of maximum growth is at x=0.82

Step-by-step explanation:

Given a logistic function

f(x)=\frac{24}{1+e^{-1.3x}}

we have to find the point of maximum growth rate for the logistic function f(x).

From the graph we can see that the carrying capacity or the maximum value of logistic function f(x) is 24 and the point of maximum growth is at y=\frac{24}{2} i.e between 0 to 12

So, we can take y=\frac{24}{2} and then solve for x.

\frac{24}{2}=\frac{24}{1+e^{-1.3x}}

⇒ 2=1+3\exp{-1.3x}

⇒ 1=3.\exp{-1.3x} ⇒ \frac{1}{3}=\exp{-1.3x}

                             ⇒ log 3=-1.3x

                             ⇒ -0.4771=-1.3.x ⇒ x=0.82

Hence, the point of maximum growth is at x=0.82


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sveticcg [70]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
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Equality Properties

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  • Addition Property of Equality
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Step-by-step explanation:

<u>Step 1: Define</u>

5x = 2

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide 5 on both sides:                    x = 2/5

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                     5(2/5) = 2
  2. Multiply:                                2 = 2

Here we see that 2 does indeed equal 2.

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