Solve for x. 4−(2x+4)=5 x=32 x=−52 x=−10 x=6 please help
1 answer:
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Answer:
The graph in the attached figure
Step-by-step explanation:
we have
------>inequality A
The solution of the inequality A is the shaded area above the dashed line
The y-intercept of the dashed line is (0,6)
The x-intercept of the dashed line is (-24,0)
The slope of the dashed line is positive m=1/4
------>inequality B
The solution of the inequality B is the shaded area above the dashed line
The y-intercept of the dashed line is (0,-1)
The x-intercept of the dashed line is (0.5,0)
The slope of the dashed line is positive m=2
The solution of the system of inequalities is the shaded area between the two dashed lines
using a graphing tool
see the attached figure
Answer:
Step by step Explanation'
To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.
For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.
Determine the maximum value of C, then the maximum value that C can have is 120/n
Let us represent X as the number of employees with high performance with a binomial distribution of
P =0.02( since the percentage of chance of achieving a high performance level is 2%)
n = 20 ( number of employees who achieve a high performance level)
The probability of X= 0 can be calculated
P( X= 0) = 0.98^n
Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)
BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,
Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2
then the maximum value that C can have is 120/n