The gravitational force acting between two objects is calculated by,
F = G x (m1 x m2) / d²
where G is the universal gravitational constant, m1 and m2 are the masses of the objects, and d is the distance between them. The distance between the spheres is twice the measure of the radius.
Substituting,
F = (6.674 x 10^-11) x (900 kg x 900 kg) / (0.40 m)²
Thus, the gravitational force between the spheres is approximately 3.378x10^-4 N.
Answer:
89–100
Step-by-step explanation:
Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...
80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90
Multiplying by 5 gives
400 ≤ 311 +x ≤ 450
Subtracting 311 gives the range for the fifth test grade.
89 ≤ x ≤ 139
Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...
89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test
Answer:
Step-by-step explanation:
Put the xs together
move the 274 to the other side, and that will be the
you need and
so square root 26 is 5.09, so about 5 when rounded
and square root 22 is 4.69, so about 4.7 when rounded
so
becomes
The size ot the "larger square" is 5cm