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Andrews [41]
3 years ago
7

Opal wanted to make some necklaces and sell them at a craft store. She made 37 necklaces and each necklace had somewhere between

72 and 77 beads. About how many beads did she use?
Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0
<h3>The total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.</h3>

Step-by-step explanation:

Here, as given: The number of necklace made by Opal  = 37

The least number of bead used in each necklace  = 72

So, if each necklace is made using the least number of beads then,

The total number of beads  used in 37 necklace =  37 x ( beads in 1 necklace)

= 37 x  72  = 2,664 beads

So, the least number of total beads used in 37 necklaces  = 2,664 beads

The highest number of bead used in each necklace  = 77

So, if each necklace is made using the highest number of beads then,

The total number of beads  used in 37 necklace =  37 x ( beads in 1 necklace)

= 37 x  77  = 2,849 beads

So, if highest number of total beads used in 37 necklaces  = 2,849 beads

Hence, the total number of beads used in making 37 necklaces is between 2,664 beads and 2,849 beads.

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(1,-7) with a slope of -5 as an equation
Liono4ka [1.6K]

Answer:

y=-5x-2

Step-by-step explanation:

y=mx+b

where m is the slope

y=-5x+b

to solve for b, which is the y intercept, plug in (1,-7)

-7=-5(1)+b

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7 0
3 years ago
A padlock has the digits 0 through 9 arranged in a circle on its face. A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is fou
stepan [7]

Answer:

The total numbers of possible combinations are 3430.

Step-by-step explanation:

Consider the provided information.

A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is four digits long. Because of the internal mechanics of the lock, no pair of consecutive numbers in the combination can be the same or one place apart on the face.

Here, for the first digit we have 10 choices.

For the second digit we have 7 choices, as the digit can't be the same nor adjacent to the first digit.

For the third digit we have 7 choices, as the digit can't be the same nor adjacent to the second digit.

For the fourth digit we have 7 choices, as the digit can't be the same nor adjacent to the third digit.

So the number of choices are:

10\times 7\times 7\times 7=10\times 7^3\\10\times 343=3430

Hence, the total numbers of possible combinations are 3430.

8 0
3 years ago
I have a question that says " jada has read 3/5 of a book. She has read 75 pages so far. How many pages are in the whole book?"
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Answer and Step-by-step explanation:

To solve, we would multiply by the reciprocal of the portion Jada has read, and multiply that number to 75.

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Now we do 75 times \frac{5}{3}/

\frac{75 * 5}{3} \\\\\\\\\frac{375}{3} \\\\\\\\125

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Ivenika [448]
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Factors of 65: 1, 5, 13, and 65.

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What is 0+0? (i obviously know it but its to give out points.)
Reptile [31]

Answer:

0

Step-by-step explanation:

0+0=0

6 0
4 years ago
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