o=nickel
O=quarter
O O O O O O O O O O + o o o =2.65
(2.50+.15=2.65)
there are 10 quarters total, and 3 nickels
Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v
70 w/m = t
15 pages - 350 w/p
She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.
60x70=4,200 words per hour (w/h).
Next you should find out how many words on 15 pages total.
350x15= 5,250.
I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.
She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.
The answer is 1 hour and 15 minutes.
I think... ;)
Answer:
25 is the correct answer because the amount of white socks out all of the socks is 2/8 which is equal to 1/4. 1/4 is 25%.
Step-by-step explanation:
cos θ = 3 / AB
When θ = 28°:
cos 28° = 3 / AB
AB = 3 / cos 28°
AB ≈ 3.4
When AB = 5.2:
cos θ = 3 / 5.2
θ = cos⁻¹(3 / 5.2)
θ ≈ 54.8°
<h3>
Answer: -i</h3>
========================================================
Explanation:
i = sqrt(-1)
Lets list out the first few powers of i
- i^0 = 1
- i^1 = i
- i^2 = -1
- i^3 = i*i^2 = i*(-1) = -i
- i^4 = (i^2)^2 = (-1)^2 = 1
By the time we reach the fourth power, we repeat the cycle over again (since i^0 is also equal to 1). The cycle is of length 4, which means we'll divide the exponent over 4 to find the remainder. Ignore the quotient. That remainder will determine if we go for i^0, i^1, i^2 or i^3.
For example, i^5 = i^1 because 5/4 leads to a remainder 1.
Another example: i^6 = i^2 since 6/4 = 1 remainder 2
Again, we only care about the remainder to find out which bin we land on.
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Turning to the question your teacher gave you, we have,
739/4 = 184 remainder 3
So i^739 = i^3 = -i
<h3>
-i is the final answer</h3>
--------------
Side notes:
- if i^a = i^b, then a-b is a multiple of 4
- Recall that the divisibility by 4 trick involves looking at the last two digits of the number. So i^739 is identical to i^39.
